I have a requirement where I need to process files based on the rest call in which I get the name of the file, I am adding it to the job parameter and using it while creating the beans.
I am creating step scope Beans for (reader,writer) and using the job parameter.I am starting the job in a new thread as I am using asynchronus task exceutor to launch the job and my question is how will the beans be created by spring when we define @StepScope
jobParametersBuilder.addString("fileName", request.getFileName());
jobExecution = jobLauncher.run(job, jobParametersBuilder.toJobParameters());
@Bean
public JobLauncher jobLauncher() {
SimpleJobLauncher jobLauncher = new SimpleJobLauncher();
jobLauncher.setJobRepository(jobRepository());
jobLauncher.setTaskExecutor(asyncTaskExecutor());
return jobLauncher;
}
@Bean
@StepScope
public ItemWriter<Object> writer(@Value ("#{jobParameters['fileName']}"String fileName) {
JdbcBatchItemWriter<Object> writer = new JdbcBatchItemWriter<>();
writer.setItemSqlParameterSourceProvider(
new BeanPropertyItemSqlParameterSourceProvider<Object>());
writer.setSql(queryCollection.getquery());
writer.setDataSource(dataSource(fileName));
return writer;
}
@Value ("#{jobParameters['fileName']}"String fileName) {
that you have provided in your question is a killer. thnx for sharing that.